# 题目

This time, you are supposed to find A+B where A and B are two polynomials.
Input
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, …, K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < … < N2 < N1 <=1000.
Output
For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.
Sample Input
2 1 2.4 0 3.2
2 2 1.5 1 0.5
Sample Output
3 2 1.5 1 2.9 0 3.2

# 分析

1.输入0 0要输出一个0；
2.第一次输入没有重复的指数，直接按下标赋值到数组里面即可。

# 源代码

//C/C++实现
#include <iostream>

using namespace std;

float num[1001];

int main(){
int n1, n2; //项数
float coef; //系数
int exp; //指数
int max_exp = -1; //最大指数
scanf("%d", &n1);
for(int i = 0; i < n1; ++i){
scanf("%d %f", &exp, &coef);
max_exp = (exp > max_exp ? exp : max_exp);
num[exp] = coef;
}
scanf("%d", &n2);
for(int i = 0; i < n2; ++i){
scanf("%d %f", &exp, &coef);
max_exp = (exp > max_exp ? exp : max_exp);
num[exp] += coef;
}
int count = 0; //项数计算
for(int i = 0; i <= 1000; ++i){
if(num[i]){
++count;
}
}
printf("%d", count);
for(int i = max_exp; i >= 0; --i){
if(num[i] != 0){
printf(" %d %.1f", i, num[i]);
}
}
printf("\n");
return 0;
}